4x^2+140x-296=0

Solution for 4x^2+140x-296=0 equation:

4x^2+140x-296=0

a = 4; b = 140; c = -296;
Δ = b2-4ac
Δ = 1402-4·4·(-296)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-156}{2*4}=\frac{-296}{8}
=-37
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+156}{2*4}=\frac{16}{8}
=2
$